10.8 - Potential Dividers
- 1What a potential divider circuit is and its purpose
- 2Calculating the output voltage of a potential divider
- 3Choosing resistance values to obtain a desired output voltage
- 4Using a potential divider for voltage calibration
- 5Issues with connecting a low resistance load
Introduction to the potential divider
A potential divider is a simple circuit containing resistors in series, across which the source voltage is divided. It allows only a fraction of the total voltage to be used a the output voltage.

Calculating the output voltage
The output voltage (Vout) depends on the resistor values and input voltage (Vs) according to this equation:
$\text{V}_{\text{out}} = \frac{\text{R}_2}{\text{R}_1 + \text{R}_2} \text{ V}_\text{s}$
Where:
- Vout = output voltage (V)
- R$_1$ = resistance of resistor 1 ($\Omega$)
- R2 = resistance of resistor 2 ($\Omega$)
- Vs = source voltage (V)
So the output voltage is always a fraction of the input voltage, determined by the resistor ratio.
Worked example - Calculating output potential
Calculate Vout for a potential divider with R1 = 560 Ω, R2 = 3.9 kΩ, and Vs = 12 V.

Step 1: Formula
$\text{V}_\text{out} = \frac{\text{R}_2}{\text{R}_1+\text{R}_2}\text{V}_\text{s}$
Step 2: convert k$\Omega$ to $\Omega$
to convert from k$\Omega$ to Ω, multiply by 1,000
3.9 k$\Omega$ = 3,900 $\Omega$
Step 3: Substitution and correct evaluation
$\text{V}_{\text{out}}\text{ = }\frac{\text{3,900}}{\text{560 + 3,900}}\times\text{ 12 = 10.49 V}$